1 """

     2 Broken bytecode objects can easily crash the interpreter.

     3 

     4 This is not going to be fixed.  It is generally agreed that there is no

     5 point in writing a bytecode verifier and putting it in CPython just for

     6 this.  Moreover, a verifier is bound to accept only a subset of all safe

     7 bytecodes, so it could lead to unnecessary breakage.

     8 

     9 For security purposes, "restricted" interpreters are not going to let

    10 the user build or load random bytecodes anyway.  Otherwise, this is a

    11 "won't fix" case.

    12 

    13 """

    14 

    15 import types

    16 

    17 co = types.CodeType(0, 0, 0, 0, '\x04\x71\x00\x00', (),

    18                     (), (), '', '', 1, '')

    19 exec co