1 #

     2 # Copyright (c) 2007-2009 Nokia Corporation and/or its subsidiary(-ies).

     3 # All rights reserved.

     4 # This component and the accompanying materials are made available

     5 # under the terms of the License "Eclipse Public License v1.0"

     6 # which accompanies this distribution, and is available

     7 # at the URL "http://www.eclipse.org/legal/epl-v10.html".

     8 #

     9 # Initial Contributors:

    10 # Nokia Corporation - initial contribution.

    11 #

    12 # Contributors:

    13 #

    14 # Description: 

    15 #

    16 

    17 	Raptor log parsing utilities.

    18 

    19 	Line-by-line based log reporting.

    20 """

    21 

    22 import re

    23 

    24 

    25 class LogItem(object):

    26 	keep = False

    27 	def __init__(self, name, pattern, keep=False, subpattern=None):

    28 		self.name = name

    29 		self.matcher = re.compile(pattern, re.I)

    30 		self.count = 0

    31 

    32 		if subpattern:

    33 			self.subpattern = re.compile(subpattern,re.I)

    34 		else:

    35 			self.subpattern = None

    36 

    37 		if keep and LogItem.keep:

    38 			self.keep = {}

    39 		else:

    40 			self.keep = None

    41 

    42 		self.subpatterncount = 0

    43 

    44 	def xml(self):

    45 		xml = "<logitem name='%s' count='%i' subpatterncount='%i' " % ( self.name, self.count,  self.subpatterncount)

    46 		if self.keep == None:

    47 			return xml + " />"

    48 

    49 		xml += ">\n"

    50 

    51 		index = self.keep.keys()

    52 		index.sort(cmp=lambda y,x: self.keep[x] - self.keep[y])

    53 		for i in index:

    54 			xml += "<match count='" + str(self.keep[i]) +"'><![CDATA[\n" + i + "]]></match>\n"

    55 		

    56 		return xml + "</logitem>"

    57 

    58 	def match(self, line):

    59 		result = self.matcher.search(line)

    60 		if result != None:

    61 			if self.keep != None:

    62 				try:

    63 					self.keep[result.group()] += 1

    64 				except:

    65 					self.keep[result.group()] = 1

    66 			if self.subpattern != None:

    67 				self.subpatterncount += len(self.subpattern.findall(line))

    68 				for i in self.subpattern.findall(line):

    69 					print i

    70 			self.count += 1

    71