diff -r 000000000000 -r 2f259fa3e83a ode/src/fastldlt.c
--- /dev/null	Thu Jan 01 00:00:00 1970 +0000
+++ b/ode/src/fastldlt.c	Tue Feb 02 01:00:49 2010 +0200
@@ -0,0 +1,381 @@
+/* generated code, do not edit. */
+
+#include <ode/matrix.h>
+
+/* solve L*X=B, with B containing 1 right hand sides.
+ * L is an n*n lower triangular matrix with ones on the diagonal.
+ * L is stored by rows and its leading dimension is lskip.
+ * B is an n*1 matrix that contains the right hand sides.
+ * B is stored by columns and its leading dimension is also lskip.
+ * B is overwritten with X.
+ * this processes blocks of 2*2.
+ * if this is in the factorizer source file, n must be a multiple of 2.
+ */
+
+static void dSolveL1_1 (const dReal *L, dReal *B, int n, int lskip1)
+{  
+  /* declare variables - Z matrix, p and q vectors, etc */
+  dReal Z11,m11,Z21,m21,p1,q1,p2,*ex;
+  const dReal *ell;
+  int i,j;
+  /* compute all 2 x 1 blocks of X */
+  for (i=0; i < n; i+=2) {
+    /* compute all 2 x 1 block of X, from rows i..i+2-1 */
+    /* set the Z matrix to 0 */
+    Z11=0;
+    Z21=0;
+    ell = L + i*lskip1;
+    ex = B;
+    /* the inner loop that computes outer products and adds them to Z */
+    for (j=i-2; j >= 0; j -= 2) {
+      /* compute outer product and add it to the Z matrix */
+      p1=ell[0];
+      q1=ex[0];
+      m11 = dMUL(p1,1);
+      p2=ell[lskip1];
+      m21 = dMUL(p2,q1);
+      Z11 += m11;
+      Z21 += m21;
+      /* compute outer product and add it to the Z matrix */
+      p1=ell[1];
+      q1=ex[1];
+      m11 = dMUL(p1,q1);
+      p2=ell[1+lskip1];
+      m21 = dMUL(p2,q1);
+      /* advance pointers */
+      ell += 2;
+      ex += 2;
+      Z11 += m11;
+      Z21 += m21;
+      /* end of inner loop */
+    }
+    /* compute left-over iterations */
+    j += 2;
+    for (; j > 0; j--) {
+      /* compute outer product and add it to the Z matrix */
+      p1=ell[0];
+      q1=ex[0];
+      m11 = dMUL(p1,q1);
+      p2=ell[lskip1];
+      m21 = dMUL(p2,q1);
+      /* advance pointers */
+      ell += 1;
+      ex += 1;
+      Z11 += m11;
+      Z21 += m21;
+    }
+    /* finish computing the X(i) block */
+    Z11 = ex[0] - Z11;
+    ex[0] = Z11;
+    p1 = ell[lskip1];
+    Z21 = ex[1] - Z21 - dMUL(p1,Z11);
+    ex[1] = Z21;
+    /* end of outer loop */
+  }
+}
+
+/* solve L*X=B, with B containing 2 right hand sides.
+ * L is an n*n lower triangular matrix with ones on the diagonal.
+ * L is stored by rows and its leading dimension is lskip.
+ * B is an n*2 matrix that contains the right hand sides.
+ * B is stored by columns and its leading dimension is also lskip.
+ * B is overwritten with X.
+ * this processes blocks of 2*2.
+ * if this is in the factorizer source file, n must be a multiple of 2.
+ */
+
+static void dSolveL1_2 (const dReal *L, dReal *B, int n, int lskip1)
+{  
+  /* declare variables - Z matrix, p and q vectors, etc */
+  dReal Z11,m11,Z12,m12,Z21,m21,Z22,m22,p1,q1,p2,q2,*ex;
+  const dReal *ell;
+  int i,j;
+  /* compute all 2 x 2 blocks of X */
+  for (i=0; i < n; i+=2) {
+    /* compute all 2 x 2 block of X, from rows i..i+2-1 */
+    /* set the Z matrix to 0 */
+    Z11=0;
+    Z12=0;
+    Z21=0;
+    Z22=0;
+    ell = L + i*lskip1;
+    ex = B;
+    /* the inner loop that computes outer products and adds them to Z */
+    for (j=i-2; j >= 0; j -= 2) {
+      /* compute outer product and add it to the Z matrix */
+      p1=ell[0];
+      q1=ex[0];
+      m11 = dMUL(p1,q1);
+      q2=ex[lskip1];
+      m12 = dMUL(p1,q2);
+      p2=ell[lskip1];
+      m21 = dMUL(p2,q1);
+      m22 = dMUL(p2,q2);
+      Z11 += m11;
+      Z12 += m12;
+      Z21 += m21;
+      Z22 += m22;
+      /* compute outer product and add it to the Z matrix */
+      p1=ell[1];
+      q1=ex[1];
+      m11 = dMUL(p1,q1);
+      q2=ex[1+lskip1];
+      m12 = dMUL(p1,q2);
+      p2=ell[1+lskip1];
+      m21 = dMUL(p2,q1);
+      m22 = dMUL(p2,q2);
+      /* advance pointers */
+      ell += 2;
+      ex += 2;
+      Z11 += m11;
+      Z12 += m12;
+      Z21 += m21;
+      Z22 += m22;
+      /* end of inner loop */
+    }
+    /* compute left-over iterations */
+    j += 2;
+    for (; j > 0; j--) {
+      /* compute outer product and add it to the Z matrix */
+      p1=ell[0];
+      q1=ex[0];
+      m11 = dMUL(p1,q1);
+      q2=ex[lskip1];
+      m12 = dMUL(p1,q2);
+      p2=ell[lskip1];
+      m21 = dMUL(p2,q1);
+      m22 = dMUL(p2,q2);
+      /* advance pointers */
+      ell += 1;
+      ex += 1;
+      Z11 += m11;
+      Z12 += m12;
+      Z21 += m21;
+      Z22 += m22;
+    }
+    /* finish computing the X(i) block */
+    Z11 = ex[0] - Z11;
+    ex[0] = Z11;
+    Z12 = ex[lskip1] - Z12;
+    ex[lskip1] = Z12;
+    p1 = ell[lskip1];
+    Z21 = ex[1] - Z21 - dMUL(p1,Z11);
+    ex[1] = Z21;
+    Z22 = ex[1+lskip1] - Z22 - dMUL(p1,Z12);
+    ex[1+lskip1] = Z22;
+    /* end of outer loop */
+  }
+}
+
+
+EXPORT_C void dFactorLDLT (dReal *A, dReal *d, int n, int nskip1)
+{  
+  int i,j;
+  dReal sum,*ell,*dee,dd,p1,p2,q1,q2,Z11,m11,Z21,m21,Z22,m22;
+  if (n < 1) return;
+  
+  for (i=0; i<=n-2; i += 2) {
+    /* solve L*(D*l)=a, l is scaled elements in 2 x i block at A(i,0) */
+    dSolveL1_2 (A,A+i*nskip1,i,nskip1);
+    /* scale the elements in a 2 x i block at A(i,0), and also */
+    /* compute Z = the outer product matrix that we'll need. */
+    Z11 = 0;
+    Z21 = 0;
+    Z22 = 0;
+    ell = A+i*nskip1;
+    dee = d;
+    for (j=i-6; j >= 0; j -= 6) {
+      p1 = ell[0];
+      p2 = ell[nskip1];
+      dd = dee[0];
+      q1 = dMUL(p1,dd);
+      q2 = dMUL(p2,dd);
+      ell[0] = q1;
+      ell[nskip1] = q2;
+      m11 = dMUL(p1,q1);
+      m21 = dMUL(p2,q1);
+      m22 = dMUL(p2,q2);
+      Z11 += m11;
+      Z21 += m21;
+      Z22 += m22;
+      p1 = ell[1];
+      p2 = ell[1+nskip1];
+      dd = dee[1];
+      q1 = dMUL(p1,dd);
+      q2 = dMUL(p2,dd);
+      ell[1] = q1;
+      ell[1+nskip1] = q2;
+      m11 = dMUL(p1,q1);
+      m21 = dMUL(p2,q1);
+      m22 = dMUL(p2,q2);
+      Z11 += m11;
+      Z21 += m21;
+      Z22 += m22;
+      p1 = ell[2];
+      p2 = ell[2+nskip1];
+      dd = dee[2];
+      q1 = dMUL(p1,dd);
+      q2 = dMUL(p2,dd);
+      ell[2] = q1;
+      ell[2+nskip1] = q2;
+      m11 = dMUL(p1,q1);
+      m21 = dMUL(p2,q1);
+      m22 = dMUL(p2,q2);
+      Z11 += m11;
+      Z21 += m21;
+      Z22 += m22;
+      p1 = ell[3];
+      p2 = ell[3+nskip1];
+      dd = dee[3];
+      q1 = dMUL(p1,dd);
+      q2 = dMUL(p2,dd);
+      ell[3] = q1;
+      ell[3+nskip1] = q2;
+      m11 = dMUL(p1,q1);
+      m21 = dMUL(p2,q1);
+      m22 = dMUL(p2,q2);
+      Z11 += m11;
+      Z21 += m21;
+      Z22 += m22;
+      p1 = ell[4];
+      p2 = ell[4+nskip1];
+      dd = dee[4];
+      q1 = dMUL(p1,dd);
+      q2 = dMUL(p2,dd);
+      ell[4] = q1;
+      ell[4+nskip1] = q2;
+      m11 = dMUL(p1,q1);
+      m21 = dMUL(p2,q1);
+      m22 = dMUL(p2,q2);
+      Z11 += m11;
+      Z21 += m21;
+      Z22 += m22;
+      p1 = ell[5];
+      p2 = ell[5+nskip1];
+      dd = dee[5];
+      q1 = dMUL(p1,dd);
+      q2 = dMUL(p2,dd);
+      ell[5] = q1;
+      ell[5+nskip1] = q2;
+      m11 = dMUL(p1,q1);
+      m21 = dMUL(p2,q1);
+      m22 = dMUL(p2,q2);
+      Z11 += m11;
+      Z21 += m21;
+      Z22 += m22;
+      ell += 6;
+      dee += 6;
+    }
+    /* compute left-over iterations */
+    j += 6;
+    for (; j > 0; j--) {
+      p1 = ell[0];
+      p2 = ell[nskip1];
+      dd = dee[0];
+      q1 = dMUL(p1,dd);
+      q2 = dMUL(p2,dd);
+      ell[0] = q1;
+      ell[nskip1] = q2;
+      m11 = dMUL(p1,q1);
+      m21 = dMUL(p2,q1);
+      m22 = dMUL(p2,q2);
+      Z11 += m11;
+      Z21 += m21;
+      Z22 += m22;
+      ell++;
+      dee++;
+    }
+    /* solve for diagonal 2 x 2 block at A(i,i) */
+    Z11 = ell[0] - Z11;
+    Z21 = ell[nskip1] - Z21;
+    Z22 = ell[1+nskip1] - Z22;
+    dee = d + i;
+    /* factorize 2 x 2 block Z,dee */
+    /* factorize row 1 */
+    dee[0] = dRecip(Z11);
+    /* factorize row 2 */
+    sum = 0;
+    q1 = Z21;
+    q2 = dMUL(q1,dee[0]);
+    Z21 = q2;
+    sum += dMUL(q1,q2);
+    dee[1] = dRecip(Z22 - sum);
+    /* done factorizing 2 x 2 block */
+    ell[nskip1] = Z21;
+  }
+  /* compute the (less than 2) rows at the bottom */
+  switch (n-i) {
+    case 0:
+    break;
+    
+    case 1:
+    dSolveL1_1 (A,A+i*nskip1,i,nskip1);
+    /* scale the elements in a 1 x i block at A(i,0), and also */
+    /* compute Z = the outer product matrix that we'll need. */
+    Z11 = 0;
+    ell = A+i*nskip1;
+    dee = d;
+    for (j=i-6; j >= 0; j -= 6) {
+      p1 = ell[0];
+      dd = dee[0];
+      q1 = dMUL(p1,dd);
+      ell[0] = q1;
+      m11 = dMUL(p1,q1);
+      Z11 += m11;
+      p1 = ell[1];
+      dd = dee[1];
+      q1 = dMUL(p1,dd);
+      ell[1] = q1;
+      m11 = dMUL(p1,q1);
+      Z11 += m11;
+      p1 = ell[2];
+      dd = dee[2];
+      q1 = dMUL(p1,dd);
+      ell[2] = q1;
+      m11 = dMUL(p1,q1);
+      Z11 += m11;
+      p1 = ell[3];
+      dd = dee[3];
+      q1 = dMUL(p1,dd);
+      ell[3] = q1;
+      m11 = dMUL(p1,q1);
+      Z11 += m11;
+      p1 = ell[4];
+      dd = dee[4];
+      q1 = dMUL(p1,dd);
+      ell[4] = q1;
+      m11 = dMUL(p1,q1);
+      Z11 += m11;
+      p1 = ell[5];
+      dd = dee[5];
+      q1 = dMUL(p1,dd);
+      ell[5] = q1;
+      m11 = dMUL(p1,q1);
+      Z11 += m11;
+      ell += 6;
+      dee += 6;
+    }
+    /* compute left-over iterations */
+    j += 6;
+    for (; j > 0; j--) {
+      p1 = ell[0];
+      dd = dee[0];
+      q1 = dMUL(p1,dd);
+      ell[0] = q1;
+      m11 = dMUL(p1,q1);
+      Z11 += m11;
+      ell++;
+      dee++;
+    }
+    /* solve for diagonal 1 x 1 block at A(i,i) */
+    Z11 = ell[0] - Z11;
+    dee = d + i;
+    /* factorize 1 x 1 block Z,dee */
+    /* factorize row 1 */
+    dee[0] = dRecip(Z11);
+    /* done factorizing 1 x 1 block */
+    break;
+    
+    default: *((char*)0)=0;  /* this should never happen! */
+  }
+}