WebKitTools/Scripts/webkitpy/tool/grammar.py
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     1 # Copyright (c) 2009 Google Inc. All rights reserved.
       
     2 # Copyright (c) 2009 Apple Inc. All rights reserved.
       
     3 #
       
     4 # Redistribution and use in source and binary forms, with or without
       
     5 # modification, are permitted provided that the following conditions are
       
     6 # met:
       
     7 #
       
     8 #     * Redistributions of source code must retain the above copyright
       
     9 # notice, this list of conditions and the following disclaimer.
       
    10 #     * Redistributions in binary form must reproduce the above
       
    11 # copyright notice, this list of conditions and the following disclaimer
       
    12 # in the documentation and/or other materials provided with the
       
    13 # distribution.
       
    14 #     * Neither the name of Google Inc. nor the names of its
       
    15 # contributors may be used to endorse or promote products derived from
       
    16 # this software without specific prior written permission.
       
    17 #
       
    18 # THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS
       
    19 # "AS IS" AND ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT
       
    20 # LIMITED TO, THE IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR
       
    21 # A PARTICULAR PURPOSE ARE DISCLAIMED. IN NO EVENT SHALL THE COPYRIGHT
       
    22 # OWNER OR CONTRIBUTORS BE LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL,
       
    23 # SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT NOT
       
    24 # LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF USE,
       
    25 # DATA, OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND ON ANY
       
    26 # THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT
       
    27 # (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE
       
    28 # OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE.
       
    29 
       
    30 import re
       
    31 
       
    32 
       
    33 def plural(noun):
       
    34     # This is a dumb plural() implementation that is just enough for our uses.
       
    35     if re.search("h$", noun):
       
    36         return noun + "es"
       
    37     else:
       
    38         return noun + "s"
       
    39 
       
    40 
       
    41 def pluralize(noun, count):
       
    42     if count != 1:
       
    43         noun = plural(noun)
       
    44     return "%d %s" % (count, noun)
       
    45 
       
    46 
       
    47 def join_with_separators(list_of_strings, separator=', ', only_two_separator=" and ", last_separator=', and '):
       
    48     if not list_of_strings:
       
    49         return ""
       
    50     if len(list_of_strings) == 1:
       
    51         return list_of_strings[0]
       
    52     if len(list_of_strings) == 2:
       
    53         return only_two_separator.join(list_of_strings)
       
    54     return "%s%s%s" % (separator.join(list_of_strings[:-1]), last_separator, list_of_strings[-1])