sbsv2/raptor/bin/raptorlog.py
author timothy.murphy@nokia.com
Fri, 30 Apr 2010 16:07:17 +0100
branchfix
changeset 511 7581d432643a
parent 3 e1eecf4d390d
permissions -rw-r--r--
fix: support new trace compiler features for preventing clashes. Automatically turn on OST_TRACE_COMPILER_IN_USE macro. Look for trace header in systemincludes. Make directories in makefile parse to prevent clashes during build. Correct path for autogen headers. Correct case issue with autogen headers on Linux.
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#
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# Copyright (c) 2007-2009 Nokia Corporation and/or its subsidiary(-ies).
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# All rights reserved.
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# This component and the accompanying materials are made available
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# under the terms of the License "Eclipse Public License v1.0"
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# which accompanies this distribution, and is available
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# at the URL "http://www.eclipse.org/legal/epl-v10.html".
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#
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# Initial Contributors:
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# Nokia Corporation - initial contribution.
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#
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# Contributors:
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#
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# Description: 
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#
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	Raptor log parsing utilities.
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	Line-by-line based log reporting.
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"""
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import re
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class LogItem(object):
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	keep = False
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	def __init__(self, name, pattern, keep=False, subpattern=None):
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		self.name = name
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		self.matcher = re.compile(pattern, re.I)
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		self.count = 0
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		if subpattern:
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			self.subpattern = re.compile(subpattern,re.I)
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		else:
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			self.subpattern = None
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		if keep and LogItem.keep:
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			self.keep = {}
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		else:
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			self.keep = None
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		self.subpatterncount = 0
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	def xml(self):
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		xml = "<logitem name='%s' count='%i' subpatterncount='%i' " % ( self.name, self.count,  self.subpatterncount)
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		if self.keep == None:
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			return xml + " />"
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		xml += ">\n"
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		index = self.keep.keys()
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		index.sort(cmp=lambda y,x: self.keep[x] - self.keep[y])
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		for i in index:
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			xml += "<match count='" + str(self.keep[i]) +"'><![CDATA[\n" + i + "]]></match>\n"
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		return xml + "</logitem>"
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	def match(self, line):
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		result = self.matcher.search(line)
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		if result != None:
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			if self.keep != None:
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				try:
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					self.keep[result.group()] += 1
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				except:
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					self.keep[result.group()] = 1
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			if self.subpattern != None:
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				self.subpatterncount += len(self.subpattern.findall(line))
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				for i in self.subpattern.findall(line):
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					print i
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			self.count += 1
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