improve resource copying speed on certain clustered build systems by forcing them to happen locally.
#
# Copyright (c) 2007-2009 Nokia Corporation and/or its subsidiary(-ies).
# All rights reserved.
# This component and the accompanying materials are made available
# under the terms of the License "Eclipse Public License v1.0"
# which accompanies this distribution, and is available
# at the URL "http://www.eclipse.org/legal/epl-v10.html".
#
# Initial Contributors:
# Nokia Corporation - initial contribution.
#
# Contributors:
#
# Description:
#
Raptor log parsing utilities.
Line-by-line based log reporting.
"""
import re
class LogItem(object):
keep = False
def __init__(self, name, pattern, keep=False, subpattern=None):
self.name = name
self.matcher = re.compile(pattern, re.I)
self.count = 0
if subpattern:
self.subpattern = re.compile(subpattern,re.I)
else:
self.subpattern = None
if keep and LogItem.keep:
self.keep = {}
else:
self.keep = None
self.subpatterncount = 0
def xml(self):
xml = "<logitem name='%s' count='%i' subpatterncount='%i' " % ( self.name, self.count, self.subpatterncount)
if self.keep == None:
return xml + " />"
xml += ">\n"
index = self.keep.keys()
index.sort(cmp=lambda y,x: self.keep[x] - self.keep[y])
for i in index:
xml += "<match count='" + str(self.keep[i]) +"'><![CDATA[\n" + i + "]]></match>\n"
return xml + "</logitem>"
def match(self, line):
result = self.matcher.search(line)
if result != None:
if self.keep != None:
try:
self.keep[result.group()] += 1
except:
self.keep[result.group()] = 1
if self.subpattern != None:
self.subpatterncount += len(self.subpattern.findall(line))
for i in self.subpattern.findall(line):
print i
self.count += 1