sbsv2/raptor/bin/raptorlog.py
author raptorbot <raptorbot@systemstesthead.symbian.intra>
Fri, 18 Dec 2009 19:57:42 +0000
branchwip
changeset 117 ecf683438dc6
parent 3 e1eecf4d390d
permissions -rw-r--r--
Don't mess around with EPOCROOT until actually entering raptor so we know what the original was Put the original epocroot back on the front of the whatcomp output. This allows what output to be either relative or absolute depending on what your epocroot is.

#
# Copyright (c) 2007-2009 Nokia Corporation and/or its subsidiary(-ies).
# All rights reserved.
# This component and the accompanying materials are made available
# under the terms of the License "Eclipse Public License v1.0"
# which accompanies this distribution, and is available
# at the URL "http://www.eclipse.org/legal/epl-v10.html".
#
# Initial Contributors:
# Nokia Corporation - initial contribution.
#
# Contributors:
#
# Description: 
#

	Raptor log parsing utilities.

	Line-by-line based log reporting.
"""

import re


class LogItem(object):
	keep = False
	def __init__(self, name, pattern, keep=False, subpattern=None):
		self.name = name
		self.matcher = re.compile(pattern, re.I)
		self.count = 0

		if subpattern:
			self.subpattern = re.compile(subpattern,re.I)
		else:
			self.subpattern = None

		if keep and LogItem.keep:
			self.keep = {}
		else:
			self.keep = None

		self.subpatterncount = 0

	def xml(self):
		xml = "<logitem name='%s' count='%i' subpatterncount='%i' " % ( self.name, self.count,  self.subpatterncount)
		if self.keep == None:
			return xml + " />"

		xml += ">\n"

		index = self.keep.keys()
		index.sort(cmp=lambda y,x: self.keep[x] - self.keep[y])
		for i in index:
			xml += "<match count='" + str(self.keep[i]) +"'><![CDATA[\n" + i + "]]></match>\n"
		
		return xml + "</logitem>"

	def match(self, line):
		result = self.matcher.search(line)
		if result != None:
			if self.keep != None:
				try:
					self.keep[result.group()] += 1
				except:
					self.keep[result.group()] = 1
			if self.subpattern != None:
				self.subpatterncount += len(self.subpattern.findall(line))
				for i in self.subpattern.findall(line):
					print i
			self.count += 1